Brilliant Wilds

How to play Brilliant Wilds

Despite the increase in remote GGY, new account registrations fell 3% to 32.4 million. There were 25.7 million active accounts at the end of the final reporting quarter.

Funds held in customer accounts also declined sharply. Operators held £886.6 million ($1.19 billion), down 13.9% from the same point a year earlier.

Retail betting diverged significantly from the wider market, with non-remote betting GGY falling 3.3% to £2.4 billion ($3.2 billion). The number of betting shops dropped for a 12th consecutive reporting period to 5,617 premises—a 3.6% annual decline (down 208 shops from March 2025).

About Brilliant Wilds

Land three or more Scatters to unlock Free Spins, with retained Position Multipliers building across hit. Random upgrades can trigger Super Mystery Symbols, Bombs or Extra Free Spins. Buy Bonus and Boost options, with wins up to 10,000x.

About Brilliant Wilds

The latest Super MILLION$ final table promises some terrific action, featuring as it does some of the best poker players on the planet.

The action will kick off with New Zealand’s David Yan in the lead, sitting as he does with 5.3 million chips, a good chunk more than his closest challengers Yuri Dzivielvski (3 million) and Niklas Astedt (2.6 million). Of those two, it is perhaps the Swede Astedt who will fancy their chances more than anyone, desperate to seal the deal having accumulated almost $2 million in winnings in the tournament series but never having closed one out to take the outright win.

Elsewhere, there are some superstars of the game who are taking their places lined up behind the leaders in pursuit of poker profit. Canadian poker legend Sam Greenwood comes into the final a little short-stack with 1.9 million chips, but he’s immediately followed by another luminary of the game in Mikita Badziakowski. The Belarussian only has 1.4 million but will be doing everything he can to get over the line. The final table betting prices are slightly different to the order in which the players find themselves in the chipcounts: